Lab Minutes Forum
Technical Discussion => Other => Topic started by: rthurber on August 21, 2013, 09:53:25 PM
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Prove that the following program always terminates for any positive integer
sub doIterminate($count) {
$num = int($count);
while($num != 1) {
if(($num%2) == 0) {
$num = $num/2;
} else {
$num = 3 * $num + 1;
}
}
}